Trial setup Standard deviation of distinction of means Huge specimen techniques

Slide1 l.jpg
1 / 23
823 days ago, 263 views
PowerPoint PPT Presentation
We wish to test the fairness of two populace implies. Tests will be ... of handymen and circuit repairmen, we will test whether the mean hourly rates for handymen and ...

Presentation Transcript

Slide 1

Looking at Two Population Means ~ Comparing Two Population Means ~ Experimental setup Standard deviation of distinction of means Large specimen methods 1 3

Slide 2

1. Experimental Setup Random examples are taken from two populaces. The examples are taken autonomously of each other. We wish to test the correspondence of two populace implies. Tests will be thought to be sufficiently huge so that the Central Limit Theorem applies (n > 30 is sufficiently substantial as a rule). 2 3

Slide 3

2. Picture of Experimental Setup Population A mean m A s.d. s A Population B mean m B s.d s B test mean specimen s.d s An example measure n A specimen mean example s.d s B test size n B 3

Slide 4

3. Standard Deviation of Difference of Means The recipe for standard deviation is If the populace standard deviations are not know, substitute the example standard deviations. 4 3

Slide 5

5. Testing Equality of Population Means The speculations of intrigue are: H 0 : populace means are equivalent ( m A = m B ) H a : m A does not equivalent m B (two-sided) H a : m A > m B (upper tail) H a : m A < m B (bring down tail) 7 3

Slide 6

6. Test Statistic for Testing Equality of Means The general type of the test measurement is For this situation it is 8 3

Slide 7

Example . The accompanying synopsis is the hourly rates of handymen and circuit repairmen, we will test whether the mean hourly rates for handymen and electrical technicians are a similar utilizing α =0.05. Summary: mean s.d. n plumbers: 45.10 3.25 40 electricians: 39.50 4.70 60 The distinction of mean is $5.60. The standard deviation of the distinction is sqrt[(3.25) 2/40 + (4.70) 2/60] = .795 The test measurement is z = 5.60/.795 = 7.04 Since 7.04 > 1.96 we reason that the populace means are distinctive. 9 3

Slide 8

~Two-Sample T-Test ~ Pooled standard deviation Test measurement Assumptions 1 3

Slide 9

Assumptions Samples are chosen arbitrarily from two populaces. The populaces have an ordinary dispersion The standard deviations of the populaces are the same. We wish to test regardless of whether the method for the populaces are the same. Despite the fact that test may apply for all specimen sizes, it is particularly proper for little example sizes. 2 3

Slide 10

2. Picture of Distributions Population circulations have a similar standard deviation, same chime shape m A m B Test to check whether there is a distinction between populace implies 3

Slide 11

Pooled Standard Deviation Since the populace standard deviations are a similar we may pool the information from the two specimens to evaluate the standard deviation of the populace. The d.f. for test A = n A - 1 and d.f. for test B = n B - 1, so we have fluctuations weighted by the their d.f's. 4 3

Slide 12

Test Statistic The test measurement is a t-measurement The reference conveyance is the t-dispersion with n A + n B - 2 d.f. 6 3

Slide 13

Example: Two plastics delivered by various strategies were tried for quality. Tests of 5 of plastic An and 4 of plastic B were gotten. Information (1000 lbs/square crawl) are given underneath. A: 5.5 6.8 6.9 5.1 6.0 mean = 6.06 s.d. = 0.79 B: 6.8 7.3 8.0 8.5 mean = 7.65 s.d. = 0.75 pooled s.d. = sqrt[ [4(0.79) 2 + 3(.75) 2 ]/7 ]= .77 t = (6.06 - 7.65)/(.77 sqrt[1/5 + 1/4]) = - 3.08 (continued) 6 3

Slide 14

Example (proceeded). The basic 2-sided t-esteem with 7 d.f. also, level of essentialness .05 is 2.365. Since - 3.08 < - 2.365, the mean qualities of An and B are announced to appear as something else. 7 3

Slide 15

A Test for the fairness of Two Variances The suspicions for testing the balance of two differences are: The populaces from which the specimens were gotten must be ordinarily disseminated. The specimens must be autonomous of each other. 3

Slide 16

Formula To test Recall that The F test has two terms for the degrees of flexibilities: that of the numerator, r 1 =n-1, and that of the denominator, r 2 =m-1, where n is the example estimate from which the bigger fluctuation was acquired. 3

Slide 17

Notes for the Use of the F test The bigger difference ought to dependably be assigned as and be put in the numerator of the equation. For a two-followed test, the α esteem must be partitioned by 2 and the basic esteem be put on the right half of the F bend. 3

Slide 18

Test of theories of the nature of 2 vars. Speculation Critical Region 3

Slide 19

EXAMPLE A restorative analyst wishes to see whether the fluctuation of the heart rates (in pulsates every moment) of smokers is not quite the same as the difference of heart rates of individuals who don't smoke. Two examples are chosen, and the information are as appeared. Utilizing α = 0.05, is there enough confirmation to bolster the claim? Smokers     Nonsmokers n = 9     m = 27 = 37     = 12 3

Slide 20

State the theories and recognize the claim. Locate the basic esteem. Utilize the 0.025 table, since α = 0.05 and this is a two-followed test. Here, d.f.n. = 9 - 1 = 8, and d.f.m. = 27 - 1 = 26. 3

Slide 21

The basic esteem is 2.73. Figure the test esteem. F =   37/12   =   3.08 Make the choice. Dismiss the invalid speculation, since 3.08 > 2.73. Outline the outcomes. There is sufficient confirmation to bolster the claim that the fluctuation of the heart rates of smokers and nonsmokers are distinctive. 3

Slide 22

Remark When the appropriations are ordinary however the Variances appear to be not equivalent ie The t-measurements ought to be dodged especially if n and m are additionally extraordinary. For this situation utilize z-test by substituting the example changes for the populace fluctuations. In the last circumstance, if n and m are extensive no issue When n and m are little utilize t-test with [r] dfs. 3

Slide 23

Use t-test with little n and m . Changes are not equivalent An equal equation for r is 3