# Section 23: Electric Potential

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Section 23: Electric Potential . Segment 23-1: Potential Contrast. The voltage between the cathode and the screen of a TV set is 22 kV. On the off chance that we accept a velocity of zero for an electron as it leaves the cathode, what is its rate just before it hits the screen?. 8.8

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Slide 1

﻿Part 23: Electric Potential Section 23-1: Potential Difference

Slide 2

The voltage between the cathode and the screen of a TV is 22 kV. In the event that we expect a speed of zero for an electron as it leaves the cathode, what is its speed just before it hits the screen? 8.8 × 10 7 m/s 2.8 × 10 6 m/s 6.2 × 10 7 m/s 7.7 × 10 15 m/s 5.3 × 10 7 m/s

Slide 3

The voltage between the cathode and the screen of a TV is 22 kV. On the off chance that we expect a speed of zero for an electron as it leaves the cathode, what is its speed just before it hits the screen? 8.8 × 10 7 m/s 2.8 × 10 6 m/s 6.2 × 10 7 m/s 7.7 × 10 15 m/s 5.3 × 10 7 m/s

Slide 4

The electric field in a district is given by E = 2 x 2 i + 3 y j where the units are in V/m. What is the adjustment in electric potential from the source to ( x , y ) = (2, 0) m? 8 V –8 V –16/3 V –24/3 V 11 V

Slide 5

The electric field in an area is given by E = 2 x 2 i + 3 y j where the units are in V/m. What is the adjustment in electric potential from the birthplace to ( x , y ) = (2, 0) m? 8 V –8 V –16/3 V –24/3 V 11 V

Slide 6

A lithium core with a charge of +3 e and a mass of 7 u, and an alpha molecule with a charge of +2 e and a mass of 4 u, are very still. They could be quickened to the same active vitality by quickening them through the same electrical potential contrast. quickening the alpha molecule through V volts and the lithium core through 2 V/3 volts. quickening the alpha molecule through V volts and the lithium core through 7 V/4 volts. quickening the alpha molecule through V volts and the lithium core through 7 V/6 volts. none of these systems.

Slide 7

A lithium core with a charge of +3 e and a mass of 7 u, and an alpha molecule with a charge of +2 e and a mass of 4 u, are very still. They could be quickened to the same dynamic vitality by quickening them through the same electrical potential distinction. quickening the alpha molecule through V volts and the lithium core through 2 V/3 volts. quickening the alpha molecule through V volts and the lithium core through 7 V/4 volts. quickening the alpha molecule through V volts and the lithium core through 7 V/6 volts. none of these systems.

Slide 8

The idea of contrast in electric potential is most nearly connected with the mechanical drive on an electron. the quantity of particles in one gram-iota. the charge on one electron. the resistance of a specific determined segment of mercury. the work per unit amount of electric charge.

Slide 9

The idea of contrast in electric potential is most nearly connected with the mechanical compel on an electron. the quantity of particles in one gram-molecule. the charge on one electron. the resistance of a specific indicated section of mercury. the work per unit amount of electric charge.

Slide 10

Charges Q and q ( Q ≠ q ), isolated by a separation d , deliver a potential V P = 0 at point P. This implies no drive is following up on a test charge put at point P. Q and q must have a similar sign. the electric field must be zero at point P. the net work in conveying Q to separation d from q is zero. the net work expected to convey a charge from vastness to point P is zero.

Slide 11

Charges Q and q ( Q ≠ q ), isolated by a separation d , deliver a potential V P = 0 at point P. This implies no compel is following up on a test charge set at point P. Q and q must have a similar sign. the electric field must be zero at point P. the net work in conveying Q to separation d from q is zero. the net work expected to convey a charge from vastness to point P is zero.

Slide 12

When +2.0 C of charge moves at consistent speed from an indicate with zero potential a point with potential +6.0 V, the measure of work done is 2 J. 3 J. 6 J. 12 J. 24 J.

Slide 13

When +2.0 C of charge moves at steady speed from an indicate with zero potential a point with potential +6.0 V, the measure of work done is 2 J. 3 J. 6 J. 12 J. 24 J.

Slide 14

The electron volt is a unit of capacitance. charge. vitality. energy. potential.

Slide 15

The electron volt is a unit of capacitance. charge. vitality. energy. potential.

Slide 16

Two parallel even plates are separated 0.40 cm separated in air. You present an oil bead of mass 4.9 × 10 – 17 kg between the plates. On the off chance that the bead conveys two electronic charges and if there were no air lightness, you could hold the bead still between the plates in the event that you kept the potential distinction between them at 60 V. 12 V. 3.0 V. 0.12 kV. 6.0 V.

Slide 17

Two parallel level plates are dispersed 0.40 cm separated in air. You present an oil bead of mass 4.9 × 10 – 17 kg between the plates. On the off chance that the bead conveys two electronic charges and if there were no air lightness, you could hold the bead still between the plates on the off chance that you kept the potential contrast between them at 60 V. 12 V. 3.0 V. 0.12 kV. 6.0 V.

Slide 18

Two parallel metal plates 5.0 cm separated have a potential distinction between them of 75 V. The electric constrain on a positive charge of 3.2 × 10 – 19 C at a point halfway between the plates is roughly 4.8 × 10 –18 N. 2.4 × 10 –17 N. 1.6 × 10 –18 N. 4.8 × 10 –16 N. 9.6 × 10 –17 N.

Slide 19

Two parallel metal plates 5.0 cm separated have a potential distinction between them of 75 V. The electric constrain on a positive charge of 3.2 × 10 – 19 C at a point halfway between the plates is around 4.8 × 10 –18 N. 2.4 × 10 –17 N. 1.6 × 10 –18 N. 4.8 × 10 –16 N. 9.6 × 10 –17 N.

Slide 20

The electrostatic potential as a component of separation along a specific line in space is appeared in chart (1). Which of the bends in diagram (2) is destined to speak to the electric field as a component of separation along a similar line?

Slide 21

The electrostatic potential as an element of separation along a specific line in space is appeared in diagram (1). Which of the bends in chart (2) is well on the way to speak to the electric field as a component of separation along a similar line?

Slide 22

Which of the focuses appeared in the chart are at a similar potential? 2 and 5 2, 3, and 5 1 and 4 1 and 5 2 and 4

Slide 23

Which of the focuses appeared in the outline are at a similar potential? 2 and 5 2, 3, and 5 1 and 4 1 and 5 2 and 4

Slide 24

Which point in the electric field in the chart is at the most noteworthy potential? 1 2 3 4 5

Slide 25

Which point in the electric field in the outline is at the most astounding potential? 1 2 3 4 5

Slide 26

Which point in the electric field in the graph is at the most minimal potential? 1 2 3 4 5

Slide 27

Which point in the electric field in the chart is at the most minimal potential? 1 2 3 4 5

Slide 28

The figure demonstrates two plates An and B. Plate A has a capability of 0 V and plate B a capability of 100 V. The dabbed lines speak to equipotential lines of 25, 50, and 75 V. A positive test charge of 1.6 × 10 – 19 C at direct x is exchanged toward point z. The electric potential vitality picked up or lost by the test charge is 8 × 10 – 18 J, picked up. 8 × 10 – 18 J, lost. 24 × 10 – 18 J, picked up. 24 × 10 – 8 J, lost. 40 × 10 – 8 J, picked up.

Slide 29

The figure demonstrates two plates An and B. Plate A has a capability of 0 V and plate B a capability of 100 V. The dabbed lines speak to equipotential lines of 25, 50, and 75 V. A positive test charge of 1.6 × 10 – 19 C at direct x is exchanged toward point z. The electric potential vitality picked up or lost by the test charge is 8 × 10 – 18 J, picked up. 8 × 10 –18 J, lost. 24 × 10 – 18 J, picked up. 24 × 10 – 8 J, lost. 40 × 10 – 8 J, picked up.

Slide 30

Chapter 23: Electric Potential Section 23-2: Potential Due to a System of Point Charges

Slide 31

Charges + Q and – Q are orchestrated at the edges of a square as appeared. At the point when the greatness of the electric field E and the electric potential V are resolved at P, the focal point of the square, we find that E ≠ 0 and V > 0. E = 0 and V = 0. E = 0 and V > 0. E ≠ 0 and V < 0. None of these is right.

Slide 32

Charges + Q and – Q are masterminded at the sides of a square as appeared. At the point when the size of the electric field E and the electric potential V are resolved at P, the focal point of the square, we find that E ≠ 0 and V > 0. E = 0 and V = 0. E = 0 and V > 0. E ≠ 0 and V < 0. None of these is right.

Slide 33

Two equivalent positive charges are put in an outer electric field. The equipotential lines indicated are at 100 V interims. The potential for line c is  100 V.  100 V.  200 V.  200 V. zero

Slide 34

Two equivalent positive charges are set in an outside electric field. The equipotential lines demonstrated are at 100 V interims. The potential for line c is  100 V.  100 V.  200 V.  200 V. zero

Slide 35

Two equivalent positive charges are put in an outer electric field. The equipotential lines indicated are at 100 V interims. The work required to move a third charge, q =  e, from the  100 V line to b is  100 eV.  100 eV.  200 eV.  200 eV. zero

Slide 36

Two equivalent positive charges are set in an outside electric field. The equipotential lines demonstrated are at 100 V interims. The work required to move a third charge, q =  e, from the  100 V line to b is  100 eV.  100 eV.  200 eV.  200 eV. zero

Slide 37

The potential at an indicate due a unit positive point charge is foun