Address 14 Images Chp. 35

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Geometrical Optics:Study of reflection and refraction of light from surfaces utilizing the beam estimation.. The beam estimate expresses that light goes in straight linesuntil it is reflected or refracted and after that goes in straight lines again.The wavelength of light must be little contrasted with the size ofthe objects or else diffractive impacts happen..

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Slide 1

´╗┐Address 14 Images Chp. 35 Opening Demo Topics Plane mirror, Two parallel mirrors, Two plane mirrors at right points Spherical mirror/Plane mirror examination in shaping picture Spherical refracting surfaces Thin focal points Optical Instruments Magnifying glass, Microscope, Refracting telescope Warm-up issue

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Geometrical Optics : Study of reflection and refraction of light from surfaces utilizing the beam estimation. The beam estimate expresses that light goes in straight lines until it is reflected or refracted and afterward goes in straight lines once more. The wavelength of light should be little contrasted with the measure of the items or else diffractive impacts happen. Reflection Refraction: Snells Law Using Fermat's Principle you can demonstrate the over two laws. It expresses that the way taken by light when heading out starting with one point then onto the next is the way that takes the most brief time contrasted with adjacent ways. n 1 n 2

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Plane mirrors Real side Virtual side Angle of frequency i = - p Normal Virtual picture Angle of reflection

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eye protest 2 1 3 Problem: Two plane mirrors make an edge of 90 o . What number of pictures are there for a question set between them? reflect

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reflect 2 4 protest reflect 5,6 1 3 Problem: Two arrangement mirrors make a point of 60 o . Discover all pictures for a point question on the bisector.

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How tall must be a mirror be for a man to see his whole appearance in it. Give H a chance to be the tallness of a man and given l a chance to be the stature of the mirror?

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i = - p amplification = 1 What happens on the off chance that we twist the mirror? Sunken mirror. Picture gets amplified. Field of view is lessened Convex mirror. Picture is lessened. Field of view expanded.

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Thin Lenses : thickness is little contrasted with question remove, picture separation, and range of ebb and flow. Uniting focal point Diverging focal point

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Thin Lens Equation Lensmaker Equation What is the sign tradition?

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p Sign Convention Real side - R Virtual side - V Light r 1 r 2 i Real question - remove p is pos on V side (Incident beams are separating) Radius of arch is pos on R side. Genuine picture - separation is pos on R side. Virtual protest - separation is neg on R side Incident beams are joining) Radius of shape is neg on the V side. Virtual picture separation is neg o the V side.

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Rules for attracting beams to find pictures A beam at first parallel to the focal hub will go through the point of convergence. A beam that at first goes through the point of convergence will rise up out of the focal point parallel to the focal hub. A beam that is coordinated towards the focal point of the focal point will go straight through the viewpoint undeflected.

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Show Fig 35-14 figure overhead Then go to case

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Virtual side Real side . . F 1 p F 2 24(b). Given a focal point with a central length f = 5 cm and protest remove p = +10 cm, locate the accompanying: i and m. Is the picture genuine or virtual? Upright or altered? Draw 3 beams. Picture is genuine, modified.

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. . r 1 r 2 F 1 p F 2 24(e). Given a focal point with the properties (lengths in cm) r 1 = +30, r 2 = - 30, p = +10, and n = 1.5, locate the accompanying: f, i and m. Is the picture genuine or virtual? Upright or rearranged? Draw 3 beams. Genuine side Virtual side Image is virtual, upright.

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Lens 1 Lens 2 +20 - 15 f 1 f 2 f 1 f 2 40 10 27. A meeting focal point with a central length of +20 cm is found 10 cm to one side of a wandering focal point having a central length of - 15 cm. On the off chance that a protest is found 40 cm to one side of the focalizing focal point, find and depict totally the last picture shaped by the separating focal point. Treat every focal point Separately.

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Lens 1 Lens 2 30 40 +20 - 15 f 1 f 2 f 1 f 2 40 10 Ignoring the separating focal point (focal point 2), the picture framed by the joining focal point (focal point 1) is situated at a separation Since m = - i 1/p 1 = - 40/40= - 1 , the picture is reversed This picture now fills in as a virtual protest for focal point 2, with p 2 = - (40 cm - 10 cm) = - 30 cm.

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Lens 1 Lens 2 30 40 +20 - 15 f 1 f 2 f 1 f 2 40 10 Thus, the picture framed by focal point 2 is found 30 cm to one side of focal point 2. It is virtual (since i 2 < 0). The amplification is m = (- i 1/p 1 ) x (- i 2/p 2 ) = (- 40/40)x(30/ - 30) =+1, so the picture has an indistinguishable size introduction from the protest.

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Optical Instruments Magnifying focal point Compound magnifying lens Refracting telescope

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